Graph y=3 y = −3 y = 3 The slopeintercept form is y = mx b y = m x b, where m m is the slope and b b is the yintercept y = mx b y = m x b Find the values of m m and b b using the form y = mxb y = m x b m = 0 m = 0 b = −3 b = 3
Graph the equation. y=-3(x-1)^2+1-Steps for Solving Linear Equation y = 5x3 y = − 5 x 3 Swap sides so that all variable terms are on the left hand side Swap sides so that all variable terms are on the left hand side 5x3=y − 5 x 3 = y Subtract 3 from both sides Subtract 3 from both sides Graph the equation \(y = \frac{1}{2}x 3\) Answer Find three points that are solutions to the equation Since this equation has the fraction \(\frac{1}{2}\) as a coefficient of x, we will choose values of x carefully We will use zero as one choice and multiples of 2 for the other choices Why are multiples of 2 a good choice for values of x?
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See explanation Explanation The graph of y = x − 3 is almost the same as y = x The difference is that every point on y = x has been lowered by 3 Thus, instead of the yintercept being at y = 0 it is at y = − 3 instead Consider the generic equation of yGraph xy=3 x − y = 3 x y = 3 Solve for y y Tap for more steps Subtract x x from both sides of the equation − y = 3 − x y = 3 x Multiply each term in − y = 3 − x y = 3 x by − 1 1 Tap for more steps Multiply each term in − y = 3 − x y = 3 x by − 1 1
Incoming Term: graph the equation y=x+3, graph the equation y=x/3−5 by plotting points, graph the equation y=x/3-5, graph the equation y=(x-3)^2-5, graph the equation. y=-3(x-1)^2+1, graph the linear equation y=x-3, graph of the equation y=x+3 represents a, graph the equation y=x^2-3, graph the following equation y=x+3, graph the equation y=-1(x-3)^2+4,
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